Originally Posted by: equatorI see it as an Amaj7(#9)
Which is not a Polychord at all, it is however an Extended chord that contains an altered 9th(aug 9).
It can function as V7.
Here you can see the tones that make this type of chord:
A major scale=A-B-C#-D-E-F#-G#-A-B-Amaj7(#9)=….1.…..3.…….5...…..7……......#9

So, it is not a flatted 3rd nor an aug2. It is an aug9.
And here is an easy fingering for that chord.

E----------0-----------
B----------X-----------
G----------5-----------
D----------6-------------
A----------4---------------
E----------5-----------------

Other names for that chord can be:
Amaj7#9
Amaj7+9
Amaj7(aug9)

It cant be a dominate 7th because the 7th in his chord is major and in dominate 7 its minor.