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equator
Registered User
Joined: 04/20/05
Posts: 558
equator
Registered User
Joined: 04/20/05
Posts: 558
12/19/2005 3:41 pm
Am7=(A,C,E,G)......Am7 first inversion=(C,E,G,A)
...............................................C6=(C,E,G,A)

Indeed
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